Discussion
For that same oil, if an additive raises \( U \) to 70, the viscosity index becomes
Answer: A
Correct answer: 60
\[ VI = \frac{100 - 70}{100 - 50} \times 100 = \frac{30}{50} \times 100 = 60. \] Note the direction: raising U moves the oil towards the poor reference L, so the index falls. U is the low-temperature viscosity, and a lower value there means the oil has thinned less on cooling, which is what a high index describes.
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