Discussion
A four input neuron has weights 1, 3, 4, 5 and their inputs are 5, 10, 2, 8 respectively. The transfer function is linear with the constant of proportionality being 3. What is/are its output ?
Answer: C
The output is 249.
The neuron first forms the weighted sum of its inputs, then applies the linear transfer function, which multiplies by 3:
\[ \begin{aligned} \text{net} &= 1(5) + 3(10) + 4(2) + 5(8) \\ &= 5 + 30 + 8 + 40 = 83 \\ y &= 3 \times 83 = 249 \end{aligned} \]
5, 30, 8, 40 are the individual weighted inputs before summing, and 83 is the net input before the transfer function is applied. 860 does not come from any step of the calculation.
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