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Four inductors having inductances of 10 mH, 5 mH, 5 mH and 2 mH are connected in parallel. Find the total inductance of the parallel combination.

  • A.10 mH
  • B.1 mH
  • C.22 mH
  • D.7 mH

Answer: B

The total inductance of the parallel combination is 1 mH. Inductors in parallel combine like resistors in parallel, when there is no mutual coupling.

\[ \frac{1}{L} = \frac{1}{10} + \frac{1}{5} \]

\[ + \frac{1}{5} + \frac{1}{2} = 1\ \text{mH}^{-1} \]

So L = 1 mH. The value 22 mH is the sum of the four inductances, which is the series value, and 10 mH and 7 mH are not the result of the parallel formula. The second option is correct.

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