Discussion
The force on a straight conductor of length \( L \) carrying current \( I \) in a uniform field \( B \) is
Answer: B
The vector form is \( I\mathbf{L} \times \mathbf{B} \), so the force is greatest when the conductor lies across the field and zero when it lies along it. The force is perpendicular to both, which is what makes a motor turn.
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