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The SI unit of magnetic dipole moment is ........ .

  • A.Cm
  • B.\(\text{Cm}^{2}\)
  • C.Cm/s
  • D.\(\text{Cm}^{2}\)/s

Answer: D

The SI unit is C m\(^{2}\)/s.

The magnetic dipole moment of a current loop is \(m = IA\), current times area, so its unit is the ampere square metre. Since one ampere is one coulomb per second:

\[ \begin{aligned} \text{A m}^{2} &= \frac{\text{C}}{\text{s}}\,\text{m}^{2} \\ &= \text{C m}^{2}/\text{s} \end{aligned} \]

The coulomb metre (C m) is the unit of the electric dipole moment, a common confusion. C m\(^{2}\) and C m/s lack the correct combination of area and time.

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