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In the EPR spectrum of an aqueous solution of VOSO4 at room temperature, the total number of hyperfine splitting signals is

  • A.3
  • B.7
  • C.5
  • D.8

Answer: D

The EPR spectrum shows 8 hyperfine lines.

VO2+ contains V(IV), d1, with one unpaired electron. Vanadium-51, nearly 100 percent abundant, has nuclear spin I = 7/2, and the electron couples to it to give 2I + 1 lines:

\[ 2\left(\tfrac{7}{2}\right) + 1 = 8 \]

In solution at room temperature the anisotropy averages out and the eight-line pattern of the vanadyl ion is seen. 3 and 5 would correspond to nuclei with I = 1 or 2, and 7 to I = 3.

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