Discussion
The 31P {H} NMR spectrum of complex (Rh(PPh3)3Cl] will exhibit :
Answer: C
The spectrum shows a doublet of doublet and doublet of triplet.
Wilkinson's catalyst, RhCl(PPh3)3, is square planar with two mutually trans phosphines and one phosphine trans to chloride. The two trans phosphines are equivalent: each signal is split by 103Rh (I = 1/2) into a doublet and by the single unique phosphorus into a further doublet, giving a doublet of doublets of intensity 2.
The unique phosphine is split by rhodium into a doublet and by the two equivalent cis phosphines into a triplet, giving a doublet of triplets of intensity 1. Options with two simple doublets or triplets ignore either the Rh-P or the P-P coupling.
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