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The energy stored in the field of an inductor carrying current \( I \) is

  • A.\( \tfrac{1}{2}LI \)
  • B.\( \tfrac{1}{2}L^2I \)
  • C.\( \tfrac{1}{2}LI^2 \)
  • D.\( LI^2 \)

Answer: C

The factor of one half arises because the current rises from zero to its final value while the flux builds, exactly as the voltage does in a capacitor. The energy may also be written as the volume integral of \( \tfrac{1}{2}\mu H^2 \) over the whole field.

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