Discussion
The reaction of Ph3PCl2 with PhNH2 primarily produces
Answer: A
The product is Ph3P=NPh.
This is the Kirsanov reaction. The amine nitrogen attacks phosphorus in Ph3PCl2, displacing chloride, and the two N-H hydrogens leave with the two chlorides as HCl (usually taken up by a base):
\[ \begin{aligned} &\mathrm{Ph_{3}PCl_{2} + PhNH_{2}} \\ &\rightarrow \mathrm{Ph_{3}P{=}NPh + 2HCl} \end{aligned} \]
The three P-Ph bonds are untouched, so the product is the iminophosphorane (phosphine imide) with all three phenyls on phosphorus. PhP=NPh, PhCl2P=NPh and Ph2ClP=NPh would all require breaking P-C bonds, which does not happen under these conditions, and PhP=NPh does not even keep phosphorus's valence.
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