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The molecule that has ONLY one lone pair of electrons on xenon is

  • A.\(\text{XeF}_{2}\)
  • B.\(\text{XeF}_{4}\)
  • C.\(\text{XeO}_{2}\text{F}_{2}\)
  • D.\(\text{XeO}_{3}\text{F}_{2}\)

Answer: C

The molecule with only one lone pair on xenon is XeO2F2.

Xenon has 8 valence electrons. Each Xe-F bond uses one of them and each Xe=O bond uses two; whatever is left over sits on xenon as lone pairs.

  • XeF2: 8 − 2 = 6 electrons, three lone pairs (linear).
  • XeF4: 8 − 4 = 4 electrons, two lone pairs (square planar).
  • XeO2F2: 8 − 4 − 2 = 2 electrons, one lone pair (see-saw).
  • XeO3F2: 8 − 6 − 2 = 0, no lone pair (trigonal bipyramidal).

So only XeO2F2 has exactly one lone pair; the fluorides have more and XeO3F2 has none.

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