Discussion
The geometry of the interhalogen compound BrF3 is :
Answer: D
The answer is Trigonal bipyramid, the arrangement of the electron pairs around bromine in BrF3.
Bromine has seven valence electrons; three bond to fluorines and the remaining four form two lone pairs, giving five electron pairs in all. Five pairs are arranged trigonal bipyramidally. The two lone pairs take equatorial positions, where they suffer the least repulsion, so the three fluorines (two axial, one equatorial) give a T-shaped molecule with F-Br-F angles near 86°.
No option offers T-shaped, so the question is answered by the electron-pair geometry. Square planar and octahedral need six pairs (as in BrF5 or ICl4-), and tetrahedral needs four.
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