Discussion
Which of the both sequences represent an increasing order of orbital energy ?
Answer: D
The sequences in increasing order are 3p, 4s, 3d, 4p & 2p, 3s, 3p, 4s.
By the (n + l) rule, orbitals fill in order of increasing n + l, and for equal n + l the one with lower n comes first: 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d and so on. Both sequences in option D follow this order.
Option A's second sequence puts 3d before 4s. Option B puts 3d before 4s in its first sequence. Option C's second sequence puts 5s before 3d and 4f before 4p, both reversed.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development