Discussion
Te2+ ion has two d electrons in its outermost shell. With the aid of Hund's rule the ground term for the d2 system will be :
Answer: B
The ground term is \(^{3}F\), with \(M_{L} = 3\) and \(M_{S} = 1\).
Apply Hund's rules to two d electrons (\(m_{l} = 2, 1, 0, -1, -2\)):
- Maximise S: put the two electrons in different orbitals with parallel spins, so \(M_{S} = \frac{1}{2} + \frac{1}{2} = 1\), S = 1, multiplicity 3.
- Then maximise L: place them in \(m_{l} = 2\) and \(m_{l} = 1\), so \(M_{L} = 3\), L = 3, an F term.
The ground term is \(^{3}F\) (with J = 2 for a shell less than half full, \(^{3}F_{2}\)), as for \(Ti^{2+}\) or \(V^{3+}\). A doublet such as \(^{2}D\) belongs to a single d electron, and a quintet (\(M_{S} = 2\)) would need four unpaired electrons.
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