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Suppose \(f_{ij}\) denotes the probability of the first visit to \(j\) from \(i\) in a Markov chain with finite state space. The following are two statements :

(I) If C is a closed communicating class of persistent states, then for any transient state \(i\) which leads to \(j, k \in C\), \(f_{ij} = f_{ik}\).
(II) If C is a single closed communicating class and if \(i \to j\) where \(i \notin C\) and \(j \in C\), then \(f_{ij} = 1\).

Which of the following is true ?

  • A.Both (I) and (II) are false
  • B.Both (I) and (II) are true
  • C.(I) is true but (II) is false
  • D.(I) is false but (II) is true

Answer: B

Both (I) and (II) are true.

(I) Inside a closed communicating class C of persistent states, once the chain enters C it stays there and visits every state of C with probability 1. So starting from a transient \(i\), the chain reaches \(j \in C\) exactly when it enters C, and the same holds for \(k \in C\). Both \(f_{ij}\) and \(f_{ik}\) equal the probability of absorption into C.

(II) In a finite chain, the states outside the closed classes are transient and are left for good with probability 1. If C is the only closed class, the chain must eventually enter C, and then it hits every state of C. So \(f_{ij} = 1\) for \(i \notin C\), \(j \in C\).

Finiteness matters for (II): with infinitely many transient states the chain could wander off and never reach C. As stated, both hold, so the other options are wrong.

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