Discussion
Which of the following options is true ?
Messages arrive on a mobile phone according to the Poisson process with rate 5 messages per hour. The probability that no message arrives during 10 : 00 am to 12 : 00 noon is :
Answer: B
The probability is e−10.
From 10:00 am to 12:00 noon is 2 hours. In a Poisson process with rate 5 per hour, the number of messages in 2 hours is Poisson with mean \(5 \times 2 = 10\), so
\[ P(N = 0) = e^{-10} \]
\(1 - e^{-10}\) is the probability of at least one message, \(2e^{-5}\) uses a one-hour mean and doubles it incorrectly, and \(e^{-2/5}\) divides the time by the rate instead of multiplying.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development