Discussion
A belt \( 650 \) mm wide carries a load whose area is \( 8 \) per cent of the square of the belt width. The load area is
Answer: B
Correct answer: 0.0338 m\(^2\)
Apply the stated fraction to the square of the belt width, in metres:
\[ A = 0.08 \times (0.650)^2 = 0.08 \times 0.4225 = 0.0338\ \mathrm{m^2} \]
Rules of this form are used for a first estimate because the load area scales with the square of the width for a given trough geometry and surcharge angle. The coefficient itself depends on the idler troughing angle and on the material's surcharge angle, so it varies with the installation.
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