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Match the pairs :

Set ISet II
(a) Gear train rotational transformer(i) \(V_{2}(s) = K_{t}\, w(s)\)
(b) Tachometer velocity sensor(ii) \(\theta_{L} = n \theta_{m}\) or \(w_{L} = n w_{n}\)
(c) DC amplifier(iii) \(\frac{X_{o}(s)}{X_{m}(s)} = \frac{-s^{2}}{s^{2} + (b/m)s + k/m}\)
(d) Acceleration sensor(iv) \(K_{a}/(s\tau + 1)\)

  • A.(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
  • B.(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
  • C.(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
  • D.(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

Answer: A

The correct code is (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii).

A gear train acts as a rotational transformer: the load angle is the motor angle times the gear ratio, \(\theta_{L} = n\theta_{m}\) (ii). A tachometer produces a voltage proportional to shaft speed, \(V_{2}(s) = K_{t}\,\omega(s)\) (i). A dc amplifier is modelled as a gain with a single time constant, \(K_{a}/(s\tau + 1)\) (iv). An accelerometer is a mass-spring-damper, giving the second-order ratio with \(-s^{2}\) in the numerator (iii).

The other codes give the tachometer the first-order amplifier model or match the gear train to the second-order accelerometer equation.

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