Discussion
If each of the odd-place digits in the number 76835 is decreased by '1' and each of the even-place digits is increased by '1' then the sum of the digits in the new number is
Answer: C
The sum of the digits is 28.
Number the places of 76835 from the left: 7 (1st), 6 (2nd), 8 (3rd), 3 (4th), 5 (5th). The odd places hold 7, 8 and 5, which each decrease by 1 to 6, 7 and 4. The even places hold 6 and 3, which each increase by 1 to 7 and 4.
The new number is 6 7 7 4 4, and its digits add up to
\[ 6 + 7 + 7 + 4 + 4 = 28 \]
A quicker check: three digits fall by 1 and two rise by 1, so the original sum of 29 falls by 1 to 28. 29 is the unchanged sum, and 26 comes from decreasing every digit.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development