Discussion
The solution of 3(2u + v) = 7 uv and 3(u + 3v) = 11 uv is _____
Answer: B
Correct answer: u = 1, v = 3/2
Putting \( u = 1 \) and \( v = \tfrac32 \) into the first equation gives \( 3(2 + \tfrac32) = 10.5 \) and \( 7uv = 7 \times \tfrac32 = 10.5 \); into the second, \( 3(1 + \tfrac92) = 16.5 \) and \( 11uv = 11 \times \tfrac32 = 16.5 \). Both hold, so that is the solution.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development