Discussion
If 19 (36) 13 and 37 (81) 28, then what is the value of 'A' in 43 (A) 38?
Answer: C
Correct answer: 25
The number in brackets is the square of the difference of the outer two: \( (19-13)^2 = 36 \) and \( (37-28)^2 = 81 \). So \[ A = (43-38)^2 = \mathbf{25} \]
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