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For a matrix A of order 3 with determinant 2, the determinant of its adjoint is

  • A.0.5
  • B.4
  • C.2
  • D.8

Answer: B

Taking determinants of \( A\,\mathrm{adj}A = (\det A) I \) for order \( n \):

\[ \det A \cdot \det(\mathrm{adj}A) = (\det A)^{n} \quad\Rightarrow\quad \det(\mathrm{adj}A) = (\det A)^{n-1} \]

\[ = 2^{3-1} = 2^{2} = 4 \]

For a 2 by 2 matrix the exponent is one and the adjoint's determinant simply equals the matrix's own.

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