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If the matrix \(\begin{bmatrix} x & -3 \\ 2 & x - 5 \end{bmatrix}\) is singular, sum of the values of \(x\) is:

  • A.5
  • B.6
  • C.0
  • D.\(-1\)

Answer: A

The sum of the values of \(x\) is 5.

A singular matrix has zero determinant:

\[ \begin{aligned} x(x - 5) - (-3)(2) &= 0 \\ x^{2} - 5x + 6 &= 0 \end{aligned} \]

The roots are \(x = 2\) and \(x = 3\), and their sum is 5 (equally, the sum of the roots of \(x^{2} - 5x + 6\) is the negative of the coefficient of \(x\)).

6 is the product of the roots, not their sum. 0 and \(-1\) cannot arise: whatever the individual roots, their sum is fixed at 5 by the coefficient of \(x\) in the quadratic.

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