Discussion
What is the output of this program?
#include <stdio.h>
#include <stdlib.h>
int main()
{
struct test
{
int i;
float f;
char c;
};
struct test *ptr;
ptr = (struct test *)malloc(sizeof(struct test));
ptr ->f = 5.5f;
printf("%f", ptr->f);
return 0;
}
Answer: C
Here test is a structure name which consist of three variables of three different data types. ptr is the pointer variable, for which the memory is allocated dynamically by using malloc() of function and then it is pointed towards the structure floating variable f. Now f is initialized with a value 5.5f and then outputted as 5.500000.
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