Discussion
In a paged memory, the page hit ratio is 0.35. The required to access a page in secondary memory is equal to 100 ns. The time required to access a page in primary memory is 10 ns. The average time required to access a page is :
Answer: C
Correct answer: 68.5 ns
With a hit ratio of 0.35, the page is found in primary memory 35 per cent of the time and must be fetched from secondary memory otherwise:
\[ 0.35\times 10 + 0.65\times 100 = 3.5 + 65 = 68.5\ \text{ns} \]
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