Discussion
Two identical cubes each of total surface area of 6 cm² are joined end to end. Which of the following is the total surface area of the cuboid so formed?
Answer: C
Each cube has total surface area 6 cm², so a single face is 1 cm² and the edge is 1 cm.
Joined end to end they form a cuboid of \( 2 \times 1 \times 1 \):
\[ \text{TSA} = 2(lb + bh + hl) = 2(2 + 1 + 2) = 10 \text{ cm}^{2} \]
The two faces that meet are sealed inside and no longer count. Adding the cubes' areas would give 12 cm², which is exactly 2 cm² too many - the pair of hidden faces.
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