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Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.

  • A.225 cm²
  • B.275 cm²
  • C.285 cm²
  • D.315 cm²

Answer: C

\[ A = \frac{1}{2}(a + b)h = \frac{1}{2}(20 + 18) \times 15 \]

\[ = \frac{1}{2} \times 38 \times 15 = 285 \text{ cm}^{2} \]

The two parallel sides are averaged, then multiplied by the perpendicular distance between them.

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