Discussion
The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square.
Answer: D
\[ \text{side of square} = \sqrt{4096} = 64 \text{ cm} \]
\[ \text{length} = 2 \times 64 = 128 \text{ cm}, \qquad \text{breadth} = 64 - 24 = 40 \text{ cm} \]
\[ \text{breadth} : \text{length} = 40 : 128 = 5 : 16 \]
That ratio is not among the choices, so the answer is none of these. The 7 : 16 on offer is close enough to catch a careless division.
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