Discussion
If radius is 18 cm and angle at center of circle is 120° then area of sector is
Answer: B
\[ A = \frac{\theta}{360} \times \pi r^{2} = \frac{120}{360} \times \pi \times 18^{2} \]
\[ = \frac{1}{3} \times 324\pi = 108\pi \]
\[ = 108 \times 3.1416 = 339.3 \text{ cm}^{2} \]
\( 120^{\circ} \) is a third of a full turn, so the sector is a third of the circle's 1017.9 cm².
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