Discussion
For the given circuit, if all the resistance values are in ohms and the source voltage V = 30 V, then find the source current.
Answer: A
The 10 ohm resistor is directly across the 30 V source. The other branch is the 11 ohm resistor in series with the 4 ohm resistor, which is 15 ohms, also directly across the source.
\[ \begin{aligned} I_{10} = \frac{30}{10} \\ &= 3\ \text{A},\qquad I_{15} = \frac{30}{15} \\ &= 2\ \text{A} \end{aligned} \]
\[ I_{source} = 3 + 2 = 5\ \text{A} \]
Equivalently the parallel combination of 10 and 15 ohms is 6 ohms and 30/6 = 5 A. The values 6 A, 10 A and 12 A come from ignoring the series resistor or adding the wrong branches. The answer is 5 A, option A.
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