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Discussion

The figure depicts stability fields of minerals P and Q. Which one of the following statements is INCORRECT?

Temperature up, pressure along: Liquid at high temperature, P at lower pressure and Q at higher pressure meet at one point; the P-Q boundary slopes up and right, the P-Liquid boundary rises gently and the Q-Liquid boundary rises more steeply

  • A.P and Q can coexist at different temperatures only if pressures are different
  • B.P and Q can coexist with liquid only at one pressure and temperature
  • C.Q has a higher melting temperature at higher pressures than at lower pressures
  • D.A reaction forming Q from P at constant pressure will require an input of heat

Answer: D

The incorrect statement is that a reaction forming Q from P at constant pressure will require an input of heat.

The P-Q boundary slopes up towards higher pressure, so at any fixed pressure Q lies on the low-temperature side and P on the high-temperature side. Forming Q from P at constant pressure therefore means crossing the boundary on cooling: P is the high-entropy phase, and the reaction releases heat rather than absorbing it.

The other statements fit the diagram. The P-Q boundary is sloping, not horizontal, so two coexistence points at different temperatures must be at different pressures. P, Q and liquid meet at a single invariant point. The Q-liquid curve rises with pressure, so Q melts at a higher temperature at higher pressure.

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