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A mixing height of \( 800 \) m with a mean wind speed of \( 4.5 \) m/s gives a ventilation coefficient of

  • A.360 m\(^2\)/s
  • B.6000 m\(^2\)/s
  • C.3600 m\(^2\)/s
  • D.178 m\(^2\)/s

Answer: C

Correct answer: 3600 m\(^2\)/s

The ventilation coefficient is the mixing height multiplied by the mean wind speed:

\[ VC = 800\ \text{m} \times 4.5\ \text{m/s} = 3600\ \text{m}^2/\text{s} \]

Dividing instead of multiplying gives \( 178 \), which is the trap in the distractors. A value of \( 3600 \) indicates reasonable dispersion; values below about \( 6000 \) are commonly taken as a warning of poor ventilation, and a shallow mixing height with light winds can drive it to a few hundred, the condition under which episodes develop.

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