Discussion
A mixing height of \( 800 \) m with a mean wind speed of \( 4.5 \) m/s gives a ventilation coefficient of
Answer: C
Correct answer: 3600 m\(^2\)/s
The ventilation coefficient is the mixing height multiplied by the mean wind speed:
\[ VC = 800\ \text{m} \times 4.5\ \text{m/s} = 3600\ \text{m}^2/\text{s} \]
Dividing instead of multiplying gives \( 178 \), which is the trap in the distractors. A value of \( 3600 \) indicates reasonable dispersion; values below about \( 6000 \) are commonly taken as a warning of poor ventilation, and a shallow mixing height with light winds can drive it to a few hundred, the condition under which episodes develop.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development