Discussion
Find the dry volume of the concrete required for 200 m\(^2\) of 20 cm thick concrete work with proportion of 1 : 2 : 4.
Answer: B
The volume of concrete work is area times thickness: \(200 \times 0.20 = 40\ \text{m}^3\). That is the wet volume. To get the dry volume of the ingredients, the wet volume is multiplied by 1.54, to allow for the voids and for the shrinkage of the dry materials when they are wetted and compacted:
\[ 40 \times 1.54 = 61.6\ \text{m}^3 \]The value of 54.3 m\(^3\) is 1.36 times and 76.4 and 80 m\(^3\) are larger factors (1.91 and 2.0), which do not correspond to the usual bulking and shrinkage factor of 1.54 to 1.57.
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