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For \(x, y \in \mathbf{R}\), define

\[ d_{1}(x, y) = \big|\, |x| - |y| \,\big| \]

and \(d_{2}(x, y) = |x^{2} - y^{2}|\). Then :

  • A.\(d_{1}\) and \(d_{2}\) are metrics on R
  • B.\(d_{1}\) is a metric on R and \(d_{2}\) is not a metric on R
  • C.\(d_{2}\) is a metric on R and \(d_{1}\) is not a metric on R
  • D.neither \(d_{1}\) nor \(d_{2}\) is a metric on R

Answer: D

Neither \(d_{1}\) nor \(d_{2}\) is a metric on R.

A metric must vanish only on equal points. Both functions see only \(|x|\):

\[ \begin{aligned} d_{1}(1, -1) &= \big|\,|1| - |-1|\,\big| = 0 \\ d_{2}(1, -1) &= |1 - 1| = 0 \end{aligned} \]

yet \(1 \neq -1\). So both fail the identity of indiscernibles. (Each is symmetric and satisfies the triangle inequality, so each is a pseudometric; they become metrics only on \([0, \infty)\).)

That rules out every option claiming that one or both are metrics. The trap is that \(d_{1}\) looks like the familiar \(|x - y|\) and passes the triangle inequality check.

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