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Consider the metric spaces \(X = (\mathbb{R}, d_{1})\) and \(Y = ([0,1], d_{2})\) with the metrics defined by \(d_{1}(x,y) = |x - y|,\ x, y \in \mathbb{R}\) and \(d_{2}(x,y) = |x - y|,\ x, y \in [0,1]\), respectively. Then, which one of the following is TRUE?

  • A.\(\left[0, \frac{1}{4}\right)\) is open in X but not in Y
  • B.\(\left[0, \frac{1}{4}\right)\) is open in Y but not in X
  • C.\(\left[0, \frac{1}{4}\right)\) is open in both X and Y
  • D.\(\left[0, \frac{1}{4}\right)\) is open neither in X nor in Y

Answer: B

\([0, \tfrac{1}{4})\) is open in Y but not in X.

In \(X = \mathbb{R}\), no open interval around 0 lies inside \([0, \tfrac{1}{4})\), because every such interval contains negative numbers. So the set is not open in X.

In Y = [0, 1] with the same metric, the open ball of radius 1/4 about 0 is \(\{y \in [0, 1] : |y| \lt \tfrac{1}{4}\} = [0, \tfrac{1}{4})\), and every other point of the set has a small ball inside it. So the set is open in Y; it equals \((-\tfrac{1}{4}, \tfrac{1}{4}) \cap [0, 1]\), open in the subspace topology. Openness depends on the ambient space, which is the point of the question.

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