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A part quotes 200 \( \mu \)A/MHz running. At 48 MHz the running current is about

  • A.9.6 mA
  • B.200 \( \mu \)A
  • C.4.2 mA
  • D.48 mA

Answer: A

Correct answer: 9.6 mA

\[ 200\ \mu\mathrm{A/MHz} \times 48\ \mathrm{MHz} = 9600\ \mu\mathrm{A} = 9.6\ \mathrm{mA}. \] The figure is quoted per megahertz because dynamic current scales with clock frequency, so it lets any operating point be estimated from one number - and it is why halving the clock roughly halves the running current, which is the first move in reducing consumption.

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