Discussion
Wheat at \( 11 \) per cent moisture is conditioned to \( 16 \) per cent. Water to be added to \( 1000 \) kg is
Answer: A
Correct answer: 59.5 kg
Water must be added to raise the moisture while the dry matter stays constant, so the added water enters both the numerator and the total:
\[ W = M \frac{b-a}{100-b} = 1000 \times \frac{16-11}{100-16} = \frac{5000}{84} = 59.5\ \mathrm{kg} \]
The distractor \( 50.0 \) comes from simply taking 5 per cent of the wheat, which ignores that the added water increases the batch mass as well. The difference of nearly 10 kg would leave the wheat short of its conditioning target.
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