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In which of the following pairs both the molecules will give pure rotational spectra ?

  • A.\(\mathrm{CH_{4}}\) and \(\mathrm{CHCl_{3}}\)
  • B.\(\mathrm{CH_{2}Cl_{2}}\) and \(\mathrm{CCl_{4}}\)
  • C.\(\mathrm{CH_{2}Cl_{2}}\) and \(\mathrm{CHCl_{3}}\)
  • D.\(\mathrm{CH_{4}}\) and \(\mathrm{CCl_{4}}\)

Answer: C

Both molecules give pure rotational spectra in the pair CH2Cl2 and CHCl3.

A molecule shows a pure rotational (microwave) spectrum only if it has a permanent dipole moment, because the rotating dipole is what interacts with the radiation. CH2Cl2 (C2v) and CHCl3 (C3v) both have permanent dipole moments.

CH4 and CCl4 are regular tetrahedra whose bond dipoles cancel, so they are microwave inactive. Every other pair contains at least one of these two non-polar molecules.

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