Discussion
[BrF4]− has :
Answer: D
[BrF4]− has sp3d2 hybridization.
Bromine has 7 valence electrons, plus 1 for the negative charge, giving 8. Four are used in bonds to F, leaving two lone pairs. With four bonding pairs and two lone pairs, there are six electron pairs around Br, arranged octahedrally (sp3d2). The two lone pairs occupy trans positions, so the ion is square planar, like XeF4, with which it is isoelectronic.
SF4 has five electron pairs (one lone pair), sp3d, and a see-saw shape, so (A) and (B) describe a different electron count. sp3 would allow only four electron pairs.
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