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The hybridization of atomic orbitals of sulphur in SF4 is

  • A.dsp\(^{2}\)
  • B.sp\(^{3}\)d\(^{2}\)
  • C.sp\(^{3}\)d
  • D.sp\(^{3}\)

Answer: C

Sulphur in SF4 is sp\(^{3}\)d hybridised.

Sulphur has six valence electrons. Four form bonds to fluorine and the remaining two make one lone pair, giving five electron pairs around the central atom. Five pairs need five hybrid orbitals, sp3d, arranged as a trigonal bipyramid; the lone pair occupies an equatorial position, so the molecule has a see-saw shape.

sp3 would allow only four pairs (as in SCl2 with two lone pairs, or a tetrahedral molecule), dsp2 gives a square planar set of four, and sp3d2 six pairs, as in SF6.

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