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The CORRECT order of ionic character (in percentage) among the following is

  • A.NaCl \(\lt\) HCl \(\lt\) HBr
  • B.HCl \(\lt\) NaCl \(\lt\) HBr
  • C.HCl \(\lt\) HBr \(\lt\) NaCl
  • D.HBr \(\lt\) HCl \(\lt\) NaCl

Answer: D

The order is HBr \(\lt\) HCl \(\lt\) NaCl.

The percentage ionic character of a bond grows with the electronegativity difference between its atoms. On the Pauling scale H is 2.20, Br 2.96, Cl 3.16 and Na 0.93, giving differences of about 0.8 for H-Br, 1.0 for H-Cl and 2.2 for Na-Cl.

So HBr is the least ionic of the three, HCl comes next, and NaCl, an ionic solid, is by far the most ionic.

The orders that put NaCl first or in the middle place a metal halide below covalent hydrogen halides, and the order HCl \(\lt\) HBr reverses the effect of chlorine being more electronegative than bromine.

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