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Choose the INCORRECT pair of MOLECULE and its SHAPE among the following:

  • A.\(SF_{4}\) Seesaw
  • B.\(BrF_{5}\) Trigonal bipyramidal
  • C.\(NH_{3}\) Trigonal pyramidal
  • D.\(XeF_{4}\) Square planar
  • E.\(ClF_{3}\) T-shape

Answer: B

The incorrect pair is \(BrF_{5}\) Trigonal bipyramidal.

Bromine in \(BrF_{5}\) has five bond pairs and one lone pair, six electron pairs in an octahedral arrangement. With one position taken by the lone pair, the molecule is square pyramidal.

The other pairs are right: \(SF_{4}\) (4 bond pairs, 1 lone pair) is see-saw; \(NH_{3}\) (3 and 1) is trigonal pyramidal; \(XeF_{4}\) (4 and 2) is square planar; \(ClF_{3}\) (3 and 2) is T-shaped.

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