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Which of the following has least mean multiple bond enthalpy (in kJ mol-1 ) at 298 K?

  • A.\(N \equiv N\)
  • B.\(C \equiv N\)
  • C.C = C
  • D.\(C \equiv O\)
  • E.C = N

Answer: C

The least is C = C.

Mean multiple bond enthalpies (kJ mol-1) from the standard table are about: C=C 611, C=N 615, C≡N 891, N≡N 946, C≡O 1070.

Triple bonds are much stronger than double bonds, which rules out the three triple-bonded options. Between the two double bonds, C=N is slightly stronger than C=C, so C=C has the lowest value.

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