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The hybridization involved in the central atom of PCl5 is

  • A.\(\mathrm{dsp^{3}}\)
  • B.\(\mathrm{sp^{3}d^{2}}\)
  • C.\(\mathrm{sp^{2}d^{2}}\)
  • D.\(\mathrm{d^{2}sp^{3}}\)
  • E.\(\mathrm{sp^{3}d}\)

Answer: E

The hybridisation of phosphorus in PCl5 is sp3d.

Phosphorus has five valence electrons. To form five bonds it promotes one 3s electron to a 3d orbital and mixes one s, three p and one d orbital, all from the third shell, into five sp3d hybrids pointing to the corners of a trigonal bipyramid.

sp3d2 and d2sp3 give six hybrid orbitals (octahedral), and sp2d2 is not a standard set. dsp3 is the label used when an inner (n-1)d orbital takes part; phosphorus uses a d orbital of the same shell, so the textbook label is sp3d.

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