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Which of the following set of compounds does not follow octet rule?

  • A.\(\mathrm{SCl_{2}}\), \(\mathrm{PF_{5}}\) and \(\mathrm{SF_{6}}\)
  • B.\(\mathrm{CH_{4}}\), \(\mathrm{PF_{5}}\) and \(\mathrm{SF_{6}}\)
  • C.\(\mathrm{PF_{5}}\), \(\mathrm{H_{2}SO_{4}}\) and \(\mathrm{SF_{6}}\)
  • D.\(\mathrm{PF_{5}}\), \(\mathrm{H_{2}SO_{4}}\) and \(\mathrm{SCl_{2}}\)
  • E.\(\mathrm{SCl_{2}}\), \(\mathrm{H_{2}SO_{4}}\) and \(\mathrm{SF_{6}}\)

Answer: C

The set that does not follow the octet rule is PF5, H2SO4 and SF6.

In each of these the central atom has more than eight electrons in its valence shell (an expanded octet): phosphorus has 10 in PF5, sulphur has 12 in SF6, and in the usual Lewis structure of H2SO4 sulphur also has 12. Elements of the third period can do this by using their d orbitals.

SCl2 obeys the octet rule (two bonds and two lone pairs on S), and so does CH4, so every set containing either of them is wrong.

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