Discussion
Assertion (A): Temperature can be used to shift selectivity between two competing reactions.
Reason (R): The reaction with the higher activation energy is favoured more strongly as the temperature rises.
Answer: B
Correct answer: Both A and R are true, and R is the correct explanation of A
Both are true and the reason gives the mechanism. The rate ratio varies as \[ \frac{k_D}{k_U} \propto \exp\left(-\frac{E_D-E_U}{RT}\right), \] so if the wanted reaction has the higher activation energy, raising the temperature favours it. If it has the lower one, the reactor should be run as cold as the throughput allows - which is why selectivity, not rate, often sets the operating temperature.
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