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A spherical particle of diameter 10 nm has a surface to volume ratio of

  • A.0.06 nm\( ^{-1} \)
  • B.10 nm\( ^{-1} \)
  • C.0.6 nm\( ^{-1} \)
  • D.6 nm\( ^{-1} \)

Answer: C

Correct answer: 0.6 nm-1

\[ \frac{S}{V} = \frac{6}{d} = \frac{6}{10} = 0.6\ \mathrm{nm}^{-1}. \] For a sphere the ratio is \( 3/r \), equivalently \( 6/d \). Working with the radius rather than the diameter gives 1.2 and is the usual slip here.

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