Discussion
A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request ? (Note that the speed of light in air is 3,00,000 km/second).
Answer: D
The best-case delay is 533.33 msec. A request goes from the client up to the satellite (40,000 km) and down to the server (40,000 km), and the response makes the same trip, so the signal travels \(4 \times 40\,000 = 160\,000\) km.
\[ t = \frac{160\,000}{300\,000} = 0.5333 \text{ s} \]
\[ t = 533.33 \text{ msec} \]
133.33 msec is a single 40,000 km hop, 266.67 msec is a one-way trip of 80,000 km, and 400 msec corresponds to 120,000 km, so none of these covers the full round trip.
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