Discussion
Suppose we have to send an E-mail with an attachment of 2.5 kbyte with 1 Gbps bandwidth. Assume that the distance between the sender and the receiver is 12000 km and the light travels at 2.4 × 108 m/s. What will be the propagation time ?
Answer: B
The propagation time is 50 ms.
Propagation time depends only on the distance and the signal speed, not on the size of the message or the bandwidth:
\[ \begin{aligned} t_p &= \frac{12000 \times 10^{3}\ \text{m}}{2.4 \times 10^{8}\ \text{m/s}} \\ &= 0.05\ \text{s} = 50\ \text{ms} \end{aligned} \]
The 2.5 kbyte attachment and the 1 Gbps bandwidth decide the transmission time instead: \(2.5 \times 8000 / 10^{9} = 20\ \mu s\), which is negligible here. None of 200, 208 or 600 ms follows from the given distance and speed.
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