Discussion
The gN value for F19 nucleus is 5.256. The resonance frequency when it is placed in a magnetic field of strength 1.0 T is (Given μN = 5.0504 × 10-27 J/T) :
Answer: A
The resonance frequency is 40 MHz.
The NMR condition is \(h\nu = g_{N}\mu_{N}B\):
\[ \begin{aligned} \nu &= \frac{5.256 \times 5.0504 \times 10^{-27} \times 1.0}{6.626 \times 10^{-34}} \\ &= \frac{2.655 \times 10^{-26}}{6.626 \times 10^{-34}} \approx 4.0 \times 10^{7}\ \text{Hz} \end{aligned} \]
That is 40 MHz. 4.0 MHz and 0.60 MHz are out by powers of ten, and 60 MHz is closer to the proton's 42.6 MHz per tesla but does not follow from these data.
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