Discussion
The value of a resistor creating thermal noise is doubled. The noise power generated is therefore
Answer: D
The available thermal noise power of a resistor is \( P_n = kTB \), where k is Boltzmann's constant, T the absolute temperature and B the bandwidth. The resistance does not appear in this expression, so doubling it leaves the noise power unchanged, option D. What does change is the noise voltage, \( v_n = \sqrt{4kTBR} \), which rises by the square root of two; but the question asks for power. Options A, B and C wrongly make the power depend on the resistance.
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